In Bash, what does the loop for i in "${animals[@]}"; do echo $i; done print?

• A. It prints the elements of the array in order.
• B. It prints only the first element.
• C. It prints all elements concatenated.
• D. It prints nothing.

Answer: (A)

The loop relies on array expansion that feeds the loop with each element as a separate item. Using "${animals[@]}" means Bash delivers every element of the array in order, one by one, to the loop. Each pass assigns the current element to i, and echo $i prints that element. Since the elements are processed in their original order, you see all elements printed, one per line, in the array’s order. If an element contains spaces, this form still treats it as a single element, and echo "$i" would print it exactly as stored.