What does the loop for ((i=0;i<5;++i)); do echo $i; done print?

• A. It runs forever.
• B. It prints 1 through 5.
• C. It prints 0 through 4, each on a new line.
• D. It prints 0 through 4, on a single line.

Answer: (C)

This uses a C-style for loop in Bash. It starts with i=0, checks i<5 before each iteration, and after each iteration runs the increment ++i. The body prints the current value of i. Since the increment happens after the body, the values seen and printed are 0, 1, 2, 3, 4. When i becomes 5, the condition i<5 is false, so the loop stops. Echo prints each value on its own line, giving 0 through 4, each on a new line.